0=-16t^2+150t-70

Solution for 0=-16t^2+150t-70 equation:

0=-16t^2+150t-70

We move all terms to the left:

0-(-16t^2+150t-70)=0

We add all the numbers together, and all the variables

-(-16t^2+150t-70)=0

We get rid of parentheses

16t^2-150t+70=0

a = 16; b = -150; c = +70;
Δ = b2-4ac
Δ = -1502-4·16·70
Δ = 18020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18020}=\sqrt{4*4505}=\sqrt{4}*\sqrt{4505}=2\sqrt{4505}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-2\sqrt{4505}}{2*16}=\frac{150-2\sqrt{4505}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+2\sqrt{4505}}{2*16}=\frac{150+2\sqrt{4505}}{32}
$